逃生收藏家的设计和阐述非常复杂。首先,我们必须坚持使用数学公式,尽管它不准确,但很容易应用:
lc =(13,000 x ge) /(rpm x 6)。
LC =排气收集器长度为厘米,从排气门测量。
GE =在每个发动机转弯中排气门保持打开状态的程度,即在分配图中,除了180º之外,从理论上讲,这是隔离阀打开排气阀,有两个维度可以使阀门更加开放时间,而AAE则可以在排气阀开放,这使阀门在入场竞赛时使阀门更加开放。
因此,GE = 180 + AAE(35º) + RCE(12º)=227º(例如)。
RPM is the number of revolutions to which the engine is turned on, or to which we want the exhaust to work in optimal conditions (sometimes we are interested that the engine has low and not high)
13,000 and 6 are always fixed values
to find out what is the optimal diameter of the tube, the following formula will have to be used:
diameter = 2 x square
root = to the unit volume of the cylinder (in case of being a 2,000 cc engine, and 4 cylinders as it will BE = 500 cc)
lc =耗尽长度,厘米,我们刚刚发现了这是先前的公式。
3,1416是PI的数字,它是固定的,还有2个。
该公式是针对直管计算的,因此,必须
使用排气收集器(我们不会将4个输出放入汽车中)直径公式用于计算排气管的主要直径,仅在这两种案例中,只有一半的位移(2000 cc)(2000 cc in Expuce in Expute)(2000 cccc in Expuce)(2000 cc in Expuce in Expute)(2000 CC)输出。
关于两个分布中的哪个问题更好,如果4,2,1或4.1或4.2,我告诉您,要根据回合获得权力,最好的是4.1,个人越长,平行管就可以到达联盟,越好。 (我们谈论的是7000、9000、10,000 rpm的转弯制度(准备好摩托车或电动机)。
为了卸下发动机的弹性曲线和高架电动机扭矩,最佳分布是4,2,1或4.2(双后插座)。
This latest distribution is mounted by the majority of atmospheric gasoline engines, eight valves and gives very good result, BMW 318 not catalyzed, Opel Corsa A, Opel Kadett ... the longer the individual tubes are until reaching the secondary wongs, the faster the engine can turn (penalties the low) and the longer the secondary tubes are the secondary tubes until reaching the primary tubes until reaching the primary fork. (您对高点处罚),尽管转弯5000圈已经很好。
我希望我解决了您的疑问,另一个世界是消音器……但这是另一天。
一切顺利。